- #1

jg370

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## Homework Statement

In a problem to determine the maximum elastic potential energy of a molecule, I have the following equation:

[tex] A= \sqrt{\frac{6.626*10^-34 Js}{2\pi}}\times(\frac{1}{(1.14*10^-26kg)(1.85*10^3N/m})^(1/4)[/tex]

## Homework Equations

## The Attempt at a Solution

The answer is [tex]4.79*10^-12 m[/tex]

I have tried to coax the definition of the Joule and Newton units to come out with an answer in meter; however I do not see how this can be made to work.

Thank you for your kind assistance

jg370