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Procedure of preparation of HCl

  1. Jan 1, 2015 #1
    1. The problem statement, all variables and given/known data
    Knowing that HCl is strong acid we want to prepare HCl solution of pH=4.2.starting from a solution of pH=2.9.Explain briefly the procedure that should be followed to do this operation.

    2. Relevant equations
    pH=-log(H3O+)
    3. The attempt at a solution

    I calculated: At beginningC(H3O+)=1.258×10^-3mol/L
    at end C(H3O+)= 6.309×10^-5mol/L
    and please I want to know is the procedure dillution?
     
  2. jcsd
  3. Jan 1, 2015 #2

    Borek

    User Avatar

    Staff: Mentor

    Yes, it is dilution. You need to find out in what ratio to mix your original acid with water.
     
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