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y = x ln x
[tex]\frac{dy}{dx} = \frac{1}{x ln x} \cdot 1[/tex]
Is that correct?
[tex]\frac{dy}{dx} = \frac{1}{x ln x} \cdot 1[/tex]
Is that correct?
I was taught that way. How did you get 1/x?SphericalStrife said:Hmm i'm not great at this but,
y = x lnx
I was gunna say.. that whenever you take the derivative of logs.. 1/function * derivative of that function
so that'd give you
y = (1/xlnx)(1/x)
How do you know it?SphericalStrife said:1/x is the known derivative of lnx