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Products of ideals

  1. Dec 13, 2005 #1
    Suppose we have a commutative ring R and ideals I and J of R such that I + J = R. I have to show that there exist positive numbers m,n such that I^m + J^n = R.

    I think the trick is just to show that I^m + J^m contains 1. Because I + J = R, I+J contains 1 so there exist i in I and j in J such that i + j = 1. Now I have to find a a^m in I^m and a b^n in J^n such that a^m + b^n = 1.
    I tried a lot of things but none of them seemed to work :(

    Can anyone give me a hint how to find these a^m and b^n ?

    Thanks in advance
  2. jcsd
  3. Dec 13, 2005 #2

    matt grime

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    Why isn't n=m=1 sufficient for your purpose?

    It might help you to realize that a typical element in I^n is not of the form a^n for a in I, but a sum of n'th powers of elements in I
    Last edited: Dec 13, 2005
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