1. The problem statement, all variables and given/known data Hi I have been stumped by this question for the past few days. Worrying since I will be sitting STEP in June! Never mind. It goes like this: A particle is projected vertically upwards with a speed of 30m/s from a point A. The point B is h metres above A. The particle moves freely under gravity and is above B for a time 2.4s. Calculate the value of h. 2. Relevant equations V=U + at V^2=U^s +2aS 3. The attempt at a solution These are my parameters: From A to B u=30 a=-9.8 s=h From B u=? a=-9.8 s=? t=2.4 I took t=2.4 as the Maximum height above B.(I am not sure about this line of reasoning!) Based on that V=0 Using V=U + at U=23.52 m/s (This seemed to make sense since particle will start decelerating at some point) So, U (at b)=23.52 m/s Considering it from A to B U=30 V=23.52 a=-9.8 S=h Using V^2=U^s +2aS h=17.7m (3s.f) But alas, it seems my answer (and probable reasoning) is wrong. Any suggestions???