Determine how far away the projectile is from the launch point when it is 50m below the launch point. Determine the max height achieved by the projectile. What is the angle that the velocity vector makes with the horizontal at the point where the projectile is -50m from launch point. V=500 m/s @ 30º angle. What is distance in horizontal and angle of velocity vector when at -50m from launch.
v = u + at - Vf^2 - Vo^2 = 2aD
The Attempt at a Solution
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