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## Homework Statement

A projectile is fired from point A at an angle above the horizontal. At its highest point, after having travled a horizontal distance D from its launch point, it suddenly explodes into 2 identical fragments that travel horizonatally with equal but opposite velocitites as measured relative to the projectile just before it exploded. If one fragment lands back at point A, how far from A (in terms of D) does the other fragment land?

## Homework Equations

V1/e-x=V1/p-x + Vp/e-x

## The Attempt at a Solution

1 is going to the right(+)

V1/e=V1/p + Vp/e

V1/e = velocity of 1 relative to earth.

V1/p= velocvity of 1 relative to projectile original

Vp/e= velocity of projectile relative to earth

2 is going to the left(-)

V2/e-x=V2/p-x + Vp/e-x

V2/e = velocity of 2 relative to earth.

V2/p= velocvity of 2 relative to projectile original

Vp/e= velocity of projectile relative to earth

This is what I have for one

X=Xo +vox*t

X=D+(V1/p + Vp/e)*t

Ok so at first I thought that the time it took for the 2nd to fall down to origin(A) was the same time it took the first to come to the ground. Then I saw it different. I realized that the 1st fragment(+) actually has a higher velocity after explosion relative to the earth. So that must mean that it could have taken longer for it to fall to the ground. I am stuck here though and I was wondering if I could get some hints.

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