1. The problem statement, all variables and given/known data Joe is in a car travelling 90km/h, following Mark in a car 20m ahead travelling 110km/h. Joe then decides to throw a water balloon at Mark at an angle of 45 degrees in order to hit Mark. What speed should the water balloon be launched? Vertical: Vi = 14m/s Vf = -14m/s a = -9.8m/s^2 t = d = 20m Horizontal: V = 14m/s t = d = 20m I used the equation d(horizontal) = v^2/g x Sin2(theta) in order to find the horizontal vector component of 14m/s which is equal to the vertical vector component, as the degree is 45. This would mean the hypotenuse is 19.8 m/s, which would be the launching speed, but how would the velocity of the two cars affect it? As well as the further ahead car going a faster speed.