Projectile magnitude and angle question

  • #1
Hello, I am currently taking AP physics and require some assistance with a problem. I have to find the magnitude and angle of the original velocity of a projectile, normally this would be no problem for me but the original height is not zero which is giving me some problems.

My givens are:
t= 4.5s
dx= 45m
h= 1.6m

I believe I can get the x component with:
delta x=vox t +1/2gt**2
45m=vox(4.5s) + 4.905(4.5s**2)
so vox= .4334

If I did the above correctly all I would need now would be the y component, the problem is I have no idea on how to find it.

Any assistance would be greatly appreciated.
 

Answers and Replies

  • #2
107
0
Please post the exact question as it appears in your book. Your method of finding the x velocity is wrong. Think, what direction is the acceleration?
 
  • #3
The problem is:
A football player punts the football so that it will have a "hang time" (time of flight) of 4.5 s and land 48 m away. If the ball leaves the player's foot 160 cm above the ground, what initial velocity must the ball have?

Also, yes I did do teh x component wrong. I think it should be:
delta x=vxt + xo
48=vx4.5 + 0
so vx= 10.66
 
  • #4
VietDao29
Homework Helper
1,423
2
Yup, you got the correct x-component. v_x = 10.66 m / s.
Now your goal is to find the initial y-component.
First, you know that the ball has a 'hang time' of 4.5 s, and it's 1.6 m above the ground. What equation should you use to find out the initial velocity with the given information?
Note that the ball has an acceleration of -g (downward).
So you can use:
[tex]x = x_0 + v_it + \frac{1}{2}at ^ 2[/tex]
to find v_i (the initial y-component).
x_0 is the ball's initial position (or height), ie: 1.6 m.
When the ball hits the ground, x = 0.
With the x-component and the y-component, can you find out the ball's initial velocity?
Viet Dao,
 
Last edited:

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