1. PF Contest - Win "Conquering the Physics GRE" book! Click Here to Enter
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Projectile Motion - 2D

  1. Jan 31, 2010 #1
    1. The problem statement, all variables and given/known data
    A football player throws a football at 40 degrees. A stationary player 31.5m downfield is ready to catch the ball. At what velocity does the player have to throw the ball in order to reach the downfield player?

    We were told the correct answer is 17.7m/s

    2. Relevant equations
    I've been trying to use this equation:
    Vy^2 = Voy^2 + 2ad

    3. The attempt at a solution
    Since, Vy is equal to zero at the peak of the trajectory (15.75m)
    So, 0=Voy^2 + 2*9.8m/s^2*15.75m
    Solve for Voy and plug it into Voy=Vo*sin(40). Than solve for Vo.

    But, I can not seem to get 17.7m/s.
  2. jcsd
  3. Jan 31, 2010 #2
    Hello Tearsandrille.

    Start off with your kinematic equations:
    [tex] x=x_o + (V Cos(\theta)) t[/tex]
    [tex] y=y_o + (V Sin(\theta)) t-\frac{1}{2} g t^2[/tex]
    What do you know? What don't you know?
    You should be able to get it from here.
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook