- #1

dethlok777

- 1

- 0

I started this problem by figuring out the velocity components for both the horizontal motion and the vertical motion of the package.

initial velocity of x=the inital velocity*cos(50.0 degrees)=62.7 m/s

initial velocity of y= the inital velocity *sin (50.0 degrees)=74.7 m/s

Then I thought I should find the time it takes for the package to hit the ground. using the equation y=initial velocity component y*t + 1/2(acceleration component of y*t*t)-->-732m=(74.7m/s)t + 1/2(-9.80m/(s*s))t*t = 22s

My question: Is this the direction I should be following to solve this problem or am I totally hosed up on this? Don't want the answer to the overall question but a hint to help me figure this out.

ps sorry about the t*t notation I could not figure out how to do superscripts or subscripts here.