- #1

terryaki

A projectile is launched from ground level at an angle of 12 degrees above the horizontal. It returns to ground level. To what value should the launch angle be adjusted, w/o changing the launch speed, so that the range doubles?

So far I tried this:

I broke the problem into its components: x & y.

FOR X: {x=Vo*COS(12)t Vox=Vo*Cos(12) a=0 t=t}

FOR Y: {y=? Voy=Vo*SIN(12) a=-9.8 m/s^2 t=t}

Then I used t=x/Vo*COS(12), then substituted that for T in the Y parts, so that:

y= tan(12)x - [(4.9 x^2)/(Vo^2*cos(12)^2)]

but then I got: x=tan(12)y, which doesn't help me at all.

I'm guessing I'm approaching this problem in a totally WRONG way!