1. The problem statement, all variables and given/known data A car is drove off a cliff at 8 m/s. it lands in the sea 3 seconds later. 2. Relevant equations a) how far does it land? b)how high is the cliff? (g = 10m/s^2) c) at what angle relative to the horizontal does it land? 3. The attempt at a solution convention chosen : upwards is positive initial velocity= 0m/s a= -g Vx=8m/s a) FROM HORIZONTAL COMPONENT Vx= x(displacement)/ t( time) 8m/s = x/3s x=24m b) FROM VERTICAL COMPONENT using the eq'n s=ut + 0.5at^2 ie. y = 0.5 gt^2 y = 0.5 (-10)(9) y= - 45 m c) ** my problem is that im not sure which eq'n to use since its relative to the horizontal there is only one... i think. Vx = Vt cosθ i have t= 3s i have x=24m i dont have V ,or at least i dont know what V exactly is. Help please?