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 Homework Statement:
 A ball is thrown from a height of 30.0m with a speed of 10.0m/s at an angle of 23.0 above the horizontal. How fast is the ball going when it hits the ground?
 Relevant Equations:

Vf^2 = Vi^2 + 2a(Delta X)
Delta Y = Vit + 1/2at^2
Vx = 10cos(23) = 9.21m/s
Vy = 10sin(23) = 3.91m/s
30 = 3.91t + 1/2(9.8)t^2
0 = t(3.91  4.9t) + 30
4.9t = 33.91
t = 6.92s
Delta X = 9.21(6.92) + 1/2(9.8)(6.92)^2
Delta X = 298.38m
Vf^2 = 9.21 + 2(9.8)(298.38)
Vf^2 = 5857.458
Vf = 76.53m/s
Vy = 10sin(23) = 3.91m/s
30 = 3.91t + 1/2(9.8)t^2
0 = t(3.91  4.9t) + 30
4.9t = 33.91
t = 6.92s
Delta X = 9.21(6.92) + 1/2(9.8)(6.92)^2
Delta X = 298.38m
Vf^2 = 9.21 + 2(9.8)(298.38)
Vf^2 = 5857.458
Vf = 76.53m/s