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## Homework Statement

A jet fighter of mass 3t climbs from ground level to a height of 10,000m

in one minute. At that time it has a horizontal component of velocity

of 241m/s and a vertical component of velocity of139m/s. find

(A) the direction in which it is travelling

(B) the speed

(C) its kinetic enregy

(D) its increase in gravitational potential energy

(E) the power delivered by its engines during the climb

**2. Relevant**

I've only been doing this for 3 weeks now, and i get some of it

but don't get most.

anyhelp would be nice..., i get that there's alot.

but I am sure its basic stuff, I am not looking for answers

just help.

## The Attempt at a Solution

My attempt

a) tan = Vx/Vy

=139/241

=0.5767

=30 degrees

just a tidbit, i know that tan(29.96 =0.5767 But how do i get 0.5767 to = 29.96?)

b) V²=Vy²+Vx²

=241²+139²

=77402

=278.2121 m/s

The answers said it = 27.8m/s, why?

the next three are where i

have even less of an idea.

c) KE=½mv² right

=0.5x3000x278.2121

=417318.15j, but that's too high,right?

the answer book said it =1.16x108j , which

freaked me out because what is with the

x? where did that come from!

d) is it to do with PE=mgh? cause i did that, but no go

e) righteo.

(sorry for any spelling errors)

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