(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

slingshot (at ground level) a balloon through a window that is at height h above the ground. kids are at max range away from window, neglecting air resistance show that d=R/2 (1 + sqrt(1-4h/R)) is the distance of the slingshot from the window

2. Relevant equations

Rmax = V[o]^2 / g also r= 4h

3. The attempt at a solution

the hint given by professor is to use the trajectory equation, we know that theta = pi/4 at max range, and that distance is v^2=Vnaught^2 + 2a(x-xnaught) but im not sure if this is the right ones to use and if so then is V^2 = 0?

any suggestions would be great,

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# Homework Help: Projectile motion different heights

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