• Support PF! Buy your school textbooks, materials and every day products Here!

Projectile Motion escalator

  • Thread starter Nax
  • Start date
  • #1
Nax
2
0

Homework Statement



You are at the mall on the top step of a down escalator when you lean over laterally to see your 1.8 m tall physics professor on the bottom step of the adjacent up escalator. Unfortunately, the ice cream you hold in your hand falls out of its cone as you lean. The two escalators have identical angles of 40 degrees with the horizontal, a vertical height of 10 m. Will the ice cream land on your professor's head? Explain. If it does land on his head, at what time and at what vertical height does that happen? What is the relative speed of the ice cream with respect to the head at the time of impact?

Homework Equations



y0i+vy0it-1/2gt^2
y0p+vy0pt


The Attempt at a Solution



I'm able to find time:

10.0-(0.400)sin(40)(t)-1/2(9.81)t^2=1.80+(0.400)sin(40)(t)
-4.905t^2-0.25115t+10.0 = 0.25115t+1.8
-4.905t^2-0.51423t+8.2 = 0
(-4.905t^2-0.51423t+8.2)*-1 = 0 * -1
4.905t^2+0.51423t-8.2 = 0

t = -b +/1 sqrt ( b^2 - 4 ac) / 2a
t = ((-0.51423 +/- sqrt( (0.51423)^2 - 4(4.905) (-8.2) ) / (4.905)*2
t = (-0.51423 +/- 12.694425)/9.81

(-)

t = -13.20866/9.81
t = -1.35

(+)

t= 12.18019525/9.81
t= 1.24

------

I'm not sure how to find the vertical height and relative speed with respect to the head at the time of impact. Insight would be greatly appreciated, thank you. :)

Homework Statement





Homework Equations





The Attempt at a Solution

 

Answers and Replies

  • #2
Nax
2
0
I know we're supposed to make use of a Galilean transformation, but I'm not sure how...
 
  • #3
199
15
[STRIKE]the question gave you the information, that both professor, ice-cream with student is on escalator. Its pretty safe to assume they have same horizontal velocity (magnitude). So, the answer is yes it will land on professor's head!!!....This should give you some insight!!![/STRIKE]

I guess I overlooked some things

I'm able to find time:

10.0-(0.400)sin(40)(t)-1/2(9.81)t^2=1.80+(0.400)sin(40)(t)
-4.905t^2-0.25115t+10.0 = 0.25115t+1.8
-4.905t^2-0.51423t+8.2 = 0
(-4.905t^2-0.51423t+8.2)*-1 = 0 * -1
4.905t^2+0.51423t-8.2 = 0
what is this value (0.400)????........You haven't mentioned anything about it in your question.
 
Last edited:

Related Threads on Projectile Motion escalator

  • Last Post
Replies
3
Views
6K
Replies
27
Views
4K
  • Last Post
Replies
2
Views
2K
  • Last Post
Replies
2
Views
1K
  • Last Post
Replies
1
Views
539
  • Last Post
Replies
8
Views
3K
  • Last Post
Replies
1
Views
5K
  • Last Post
Replies
1
Views
1K
Replies
6
Views
18K
Top