Hi guys, I have a Homework problem that is related to Projectile Motion. It is said a projectile is fired form a surface(level ground) at an angle A, above the horizonal. so here is the question, there is another angle B, which reachs the same Max high with angel A, how can I prove that(adsbygoogle = window.adsbygoogle || []).push({});

tanB=(1/2)tanA?

The graph showed the path of angle A is a paraola and has a range R, but the path of angle B is only a stright line to the Max High which is H.

I know that Time or the vertical V is going to be the key since they used the same time to reach the same high, but I just couldn't get it right, with all the subs. so would u please give me a hint for that? thanks much!

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# Homework Help: Projectile Motion Graph Help

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