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Projectile motion gun help

  1. Feb 9, 2012 #1
    1. The problem statement, all variables and given/known data

    7. During World War I, the German army bombarded Paris
    with a huge gun referred to, by the Allied Forces, as “Big
    Bertha.” Assume that Big Bertha fired shells with an initial
    velocity of 1.1 x 10^3 m/s [45° above the horizontal].

    (a) How long was each shell airborne, if the launch point was the same as the landing point

    2. Relevant equations

    dy = v1xT+1/2ax X t^2

    3. The attempt at a solution

    v1 = 1.1 x 10^3
    a= -9.81
    t = ?
     
  2. jcsd
  3. Feb 9, 2012 #2
    I assume "by the same point as the landing point" means the same y coordinate. If the point was the same the gun would be firing straight up.

    Anyway, since the gun is at a 45 degree angle, you can find the y component of the initial velocity, and you know the acceleration of gravity. Just use the equation x = x0 + v0t + .5at^2 to solve for t.
     
  4. Feb 9, 2012 #3
    What would x equal

    t = Squared root x-.5(-9.81)

    thanks in advance
     
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