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Projectile Motion - Hard

  1. Mar 13, 2010 #1
    1. The problem statement, all variables and given/known data
    A shell is fired with a muzzle velocity of 350ms/s at a target 1000m away. Calculate two angles at which the shell can be fired .


    2. Relevant equations
    I think these equations might help...
    v=u+at
    s=ut+1/2at^2
    v^2=u^2 + 2as
    Hope these eqations are right.

    3. The attempt at a solution
    I thought about maybe this way:
    cos(theta)=...
    Sorry that is as far as I can go...
    Thanks for any help.
     
  2. jcsd
  3. Mar 13, 2010 #2

    tiny-tim

    User Avatar
    Science Advisor
    Homework Helper

    Hi Awsom Guy! :smile:

    (have a theta: θ and try using the X2 tag just above the Reply box :wink:)

    Yes, those three equations will solve any constant acceleration problem.

    The trick in this case is to write two lots of equations, one for the horizontal components of velocity (with a = 0), and one for the vertical (with a = -g).

    Call the time taken "t", and the launch angle θ, and get two simultaneous equations from which you can eliminate t to find θ. :smile:
     
  4. Mar 14, 2010 #3
    Ok I will try...
     
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