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## Homework Statement

This is a projectile motion problem, providing only the maximum height the object reaches and the angle that it leaves the ground, and asking to find the speed at which the object must leave in order to reach that max height:

The object leaves the ground at 45 degrees and reaches a max height of 12 feet. With what speed must the object leave the ground to reach that height?

## Homework Equations

y-direction:

where V

_{oy}= V

_{o}sin 45,

y displacement (12 feet) = V

_{oy}t + (0.5)(-9.8m/s

_{2})t

^{2}

V

_{o}= (V

_{oy}) / (sin 45)

## The Attempt at a Solution

I feel like I'm going in circles every time I attempt to solve this problem, almost like I don't have enough information, even though I know that I do.

I've gotten as far as this:

3.66 m = (V

_{o})(sin 45)t - 4.9t

^{2}

I will appreciate any help you can give me. I think I am looking at it wrong, but I can't figure out how else to do so.

Thanks in advance,

Alex