Q: A small ball rolls horizontally off the edge of a tabletop that is 1.23 m high. It strikes the floor at a point 1.96 m horizontally away from the edge of the table. (a) How long is the ball in the air? (b) What is its speed at the instant it leaves the table?(adsbygoogle = window.adsbygoogle || []).push({});

So this is what I did, i treated the vertical and horizontal motions seperately. And for (a) I solved for the time by using the constant acceleration equation, with y-yo=-1.23, a=-9.8 m/s^2 and Voy=0. Using those values I got t= .50s. I then analyzed the horizontal motion, but I'm not understanding how to get the speed at the instant it leaves the table since at t=.50s would be the speed at which it hits the ground, how do I get the time at the instant it leaves the table in order to use the constant acceleration formula? Any help at all is appreciated, thanks

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# Homework Help: Projectile motion (I think)

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