- #1

- 8

- 0

a.) How long does it take for the ball to land?

6.39s

b.) Where does it land?

6390m

c.) What is its velocity when it lands?

I get the a and b part....but i just don't understand what am i supposed to do with c.)

Thx for helping =]

You are using an out of date browser. It may not display this or other websites correctly.

You should upgrade or use an alternative browser.

You should upgrade or use an alternative browser.

- Thread starter blue__boy
- Start date

- #1

- 8

- 0

a.) How long does it take for the ball to land?

6.39s

b.) Where does it land?

6390m

c.) What is its velocity when it lands?

I get the a and b part....but i just don't understand what am i supposed to do with c.)

Thx for helping =]

- #2

- 325

- 0

Because the y and x axes are perpendicular to each other, you are able to use pythagoras' theorem to calculate the total velocity (the hypotenuse in this case).

- #3

- 8

- 0

oh....i am having trouble finding the vertical velocity too.....

- #4

- 325

- 0

height = 200m

acceleration = -9.81ms

we can use the constant acceleration formulae: v

Share: