Consider a particle with initial velocity [tex]v[/tex] that has magnitude 12.0m/s and is directed 60.0 degrees above the negative x axis. 1.) What is the x component [tex]v_x[/tex] of [tex]v[/tex](velocity)? Express your answer in meters per second. a.) [tex]v_x = ____[/tex] well i drew the picture where the negative x-axis was located, and did sin(60)*12 = 10.392, but since it's where the negative x-axis is, it'll be -10.392 right? 2.) What is the y component [tex]v_y[/tex] of [tex]v[/tex](velocity)? a.) [tex]v_y = ____[/tex] well i kinda did the same thing as for the first question, cos(60)*12 = 6m/s are these two correct?