A daring swimmer dives off a cliff with a running horizontal leap, as shown in the figure. http://smg.photobucket.com/albums/v113/apotheothenai/?action=view¤t=1011380A.jpg Part A) What must the diver's minimum speed be just as she leaves the top of the cliff so that she will miss the ledge at the bottom, which is 1.50m wide and 9.50m below the top of the cliff? I tried to use y = y0 + vy0*t - 1/2 * g * t^2 and then x = vx0 * t y = y0 + vy0*t - 1/2 * g * t^2 0 = 9.50 + 0*t - 1/2 * 9.8 * t^2 (plugged stuff in) 0 = 9.50 - 4.9 *t^2 (simplified) -t^2 = 4.6 (square root of both sides) t = 2.14 Then, x = vx0 * t x = 1.50 * 2.14 x = 3.14 It didn't work... :/ I still don't know what I'm doing in this class. Part B) What must the diver's initial speed be in miles per hour? - I know this is a dumb question, but will this be the same as the minimum speed, except in MPH?