A football is kicked at ground level with a speed of 40.0 m/s at an angle of 39.0° to the horizontal. How much later does it hit the ground?(adsbygoogle = window.adsbygoogle || []).push({});

X0= 0m Y0= 0m

X= ? Y= 0 m

Vx=? Vy= ?

Ax=0 m/s/s Ax=-9.8 m/s/s

T=?

V= 40.0 m/s

Theta= 39.0

Vx= 40.0 Cos (39.0) = 10.67 m/s

Vy= 40.0 Sin (39.0)= 38.55 m/s

0= 38.55T - 4.9 T^2

-38.55 +/- sqrt ((38.55)^2-4(-4.9)(0))/ 2(-4.9)

-38.55 +/- 38.55/-9.8

T= 0 and 7.87 seconds <-------------------------------I dont belive this is right. Could someone help me determine where I wondered astray?

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# Projectile Motion of football

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