A cannon can shoot whatever cannons shoot at different angles to the horizon, but with the same initial velocity. At what angle does the cannon shoot to a maximal distance? What would be that angle on the moon?
- d is the total horizontal distance travelled by the projectile.
- v is the velocity at which the projectile is launched
- g is the gravity
- θ is the angle at which the projectile is launched
- y0 is the initial height of the projectile
The Attempt at a Solution
The maximum angle would be pi/4 (I am assuming), however if the projectile velocity was great enough to break the moon's escape velocity then the maximum distance could be given at an angle of pi/2. Thoughts?