1. The problem statement, all variables and given/known data A rocket is launched at an angle of 36.87º (sin=0.6 cos=0.8) with an acceleration of 30m/s² for 20s (fuel runs out). Find a) total time of flight b) horizontal range. 2. Relevant equations 3. The attempt at a solution for the first 20 seconds: v= 30 * 20 = 600m/s d=30 * 20² * 0.5 = 6000m so vertical distance is= 6000 * 0.6 = 3600m and horizontal distance is= 6000 * 0.8 = 4800m fuel runs out vertical speed is v= 600 * 0.6 = 360m/s 0 = 360 - 10*t .: t=36s (time to reach max height) max height is= 3600 + 360*36 - 10*36²*0.5 = 10,080m after reaching max height 10080 = 10 * t² * 0.5 .: t=45s (time to land) t=36+45=81s (amount of time gravity is doing it's job to make it fall) horizontal speed is v= 600*0.8 = 480m/s horizontal distance = 480 * 81 = 38880m total horizontal distance = 4800 + 38880 = 43680m total time of flight = 20 + 81 = 101s Well, it's wrong. The answer should be 41,4km and 125s. Help me please, thanks in advance.