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Homework Help: Projectile Motion PLEASE HELP MIDTERM TOMMOROW

  1. Nov 15, 2007 #1
    Projectile Motion PLEASE HELP MIDTERM TOMMOROW!!!

    1. A ball is launched with a velocity of 1000m/s at some angle theta. The ball must travel 2000m in the x dir and land 800m in the y dir on a plateau. What theta should the ball be shot at to make this happen.



    2. y=y0 +v0t -.5gt^2



    3. I solved for t using x=v0cos(theta)t and plugged that into the y equation and got one solution. The answer key says theres two solutions. One at 20 something, which is the one i got and also one at 89.4 degrees. Can someone show me how to get the other/both solutions


    THANKS!!!!!! I appreciate it
     
  2. jcsd
  3. Nov 15, 2007 #2
    You should use the formula
    y=x tan theta - [tex]\stackrel{gx^2}{2u^2cos^2 theta}[/tex]

    THis formula is combined by
    verticial component using s=ut+1/2 at^2
    horizontal component v=s/t
     
  4. Nov 15, 2007 #3
    i used that equation and still only got 22.4 degrees at the sole solution.... 89.4 doesnt seem to fit. Is there an error in the answer key?
     
  5. Nov 15, 2007 #4
    i also get the 22.4 degree
    but it is acceptable that there is another angle is the answer.....
    however I forget how to solve it ~sorry
     
  6. Nov 15, 2007 #5
    ok thanks anyway!
     
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