The record distance for the hammer throw is about 87m. to achieve this distance, an athlete must produce a centripetal acceleration of nearly 711 m/s^2.
a) Given a radius of 1.21 m calculate the speed of the ball when it is released
b) The athlete lets go when the ball is 2.0 m above the ground moving at an angle of 42 degrees above the horizontal. Determine the range. Ignore any air friction
The Attempt at a Solution[/B]
Solved part a and got a velocity of 29.33 m/s. Having an issue with b, i have the solution manuals solution but i don't quite understand why they did certain things in their process. For one, why did they find the final velocity in the y component, why not just immediately find the time? And, they used displacement as -2....which makes sense because its a displacement of -2 metres, but they used positive 9.8 as the acceleration. Why was -9.8 not used and why did they even find the final velocity...why not just go straight to the time using a different kinematic equation? The attached pics contain my solution and the textbooks solution.
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