- #1
RjD12
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Homework Statement
At a time t, a projectile is measured to have a height Y = 12 m above the ground and a velocity v = 4 m/s at an angle (theta) = 42 with respect to to the horizontal. At what horizontal positions is the particle at a height 3/4 Y ?
Height= 12 m
Velocity= 4 m/s
Angle= 42 degrees
Homework Equations
I believe both the range equation x= x0 + V0xt and y= y0 + V0yt - (1/2)gt2
The Attempt at a Solution
I tried to to use the second equation, but I had trouble with time since it was not given. I used 4sin(42) for V0y, but I don't think it helped me much.
This should be simple, I can tell, but I am just stuck.