1. The problem statement, all variables and given/known data At a time t, a projectile is measured to have a height Y = 12 m above the ground and a velocity v = 4 m/s at an angle (theta) = 42 with respect to to the horizontal. At what horizontal positions is the particle at a height 3/4 Y ? Height= 12 m Velocity= 4 m/s Angle= 42 degrees 2. Relevant equations I believe both the range equation x= x0 + V0xt and y= y0 + V0yt - (1/2)gt2 3. The attempt at a solution I tried to to use the second equation, but I had trouble with time since it was not given. I used 4sin(42) for V0y, but I don't think it helped me much. This should be simple, I can tell, but I am just stuck.