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## Homework Statement

Points P and Q are in the same horizontal plane at a distance d metres apart. A projectile is shot from P in the vertical plane through PQ towards Q with a speed v m/s at an angle θ. Simultaneously another particle is shot from Q in the same vertical plane towards P with a speed of 2m/s at an angle of elevation α .

Find an expression for the distance between the two particles when one is vertically above the other one and hence prove that they collide if [itex] sin \alpha = \frac{1}{2} sin\theta.[/itex]

If [itex]\theta= \frac{1}{3}\pi [/itex] prove that they collide at a point above the level of PQ if...

[tex]v^2 > \frac{gd(\sqrt{13}-1)}{6\sqrt{3}}[/tex]

## Homework Equations

equations of motion

## The Attempt at a Solution

I just don't know how to approach this one at all. I don't want to just be given the answer, just some advice or help in how to approach the problem and any assumptions would be very very much appreciated.

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