Projectile motion question need help

[richardjoe05]

A golfer drives a golf ball 310.24 m down the fairway. If the ball is launched at an angle of 24.5 o to the horizontal, what is the maximum height attained by the ball during its flight?


H=1/2gt^2

 

[vik10622]

The maximum height attained is given by $$H = \frac{u^2 \sin^2 \theta}{2 g}$$ where u is the magnitude of the initial velocity provided and θ the angle with the horizontal.

The range of the projectile is $$R = \frac{u^2 \sin 2 \theta}{g}$$ which is given to be 310.24 m.

Thus we have $$H = \frac{R}{4} \tan \theta$$