# Homework Help: Projectile motion question need help

1. Oct 8, 2012

### richardjoe05

A golfer drives a golf ball 310.24 m down the fairway. If the ball is launched at an angle of 24.5 o to the horizontal, what is the maximum height attained by the ball during its flight?

H=1/2gt^2

2. Mar 12, 2013

### vik10622

The maximum height attained is given by $$H = \frac{u^2 \sin^2 \theta}{2 g}$$ where u is the magnitude of the initial velocity provided and θ the angle with the horizontal.

The range of the projectile is $$R = \frac{u^2 \sin 2 \theta}{g}$$ which is given to be 310.24 m.

Thus we have $$H = \frac{R}{4} \tan \theta$$