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**An artillery unit has a 105 mm howitzer with shells that leave the muzzle at Velocity 472 m/s. Firepower fixed but angle at which it is fired (60[tex]\circ[/tex]) is not.**

*A*What should you do? Increase or decrease the angle?*B*As an artillery officer in physics training, where di the shot first land?*determine time shell takes to reach max height and use that to figure out total time for shell to hit the ground***For**

V

V

[tex]\theta[/tex] = 30[tex]\circ[/tex]

And then I have no idea where to go from there.

*A*I know I have to decrease the angle, why? Not sure. Here's what I did for*A*V

_{xo}= 472 cos 60 = 236 m/sV

_{yo}= 472 sin 60 = 409 m/s[tex]\theta[/tex] = 30[tex]\circ[/tex]

*B*Time, Using 10 as g: V_{y}= V_{yo}- gT --> 0=409 - 10T ---> T= 40.9 seconds to max height.And then I have no idea where to go from there.