# Projectile Motion Question

## Homework Statement

Hello i'd apprcieate it if someone could help me with this projectile motion problem.

A projectile off mass 33.6 grams is thrown from a hight of 1 meter of the ground at an angle of 60 degress, it lands 10 meters away from the point it was thrown.

What is the peak vertical distance?
What is Vi?

## Homework Equations

(1) V = U+at^2

(2) s = 1/2 (U+V)t

(3) s = Ut + 1/2 at^2

(4) V^2 = U^2 +2as

## The Attempt at a Solution

I tried to do it in two parts:

(1)

U = ViSIN60

V = 0

a = -9.81 m/s^2

s1 = ?

t = ?

(2)

U = 0

V = ?

a = -9.81

Stotal = S1 + 1 meter

t2 = ?

and then for the horizontal:

U = ViCOS60

V = ?

a = 0

S = 10 meters

ttotal = t1 + t2

i'm really stuck if anyone can give me any tips i will really appreciate it. thank youuuuuu :) :) :)

Jenny

You can use $$v^2=u^2-2gh_{max}$$ to get the max height.