Hello, I am not completely sure how to attempt this problem but I have given it a shot. If anyone knows how to do this please look it over, or post your attempt. Thank you! 1. The problem statement, all variables and given/known data An object was shot at an angle of 49 degrees and landed 60m away at the same height. The initial velocity was 23m/s. WHat is: The length of time that the object was in the air The maximum height it reached 2. Relevant equations d=vt d=(u+v/2)t 3. The attempt at a solution horizontal v=? d=60m t=? vertical u=23m/s v=-23m/s a=-9.8m/s^2 d=0m t=? t=v-u/a t=-23m/s-23m/s/-9.8m/s^2 t=4.7s v=d/t v=60m/4.7s v=13m/s v=13m/s d=30m/s t=? t=d/v t=2.3s u=23m/s v=0m/s a=-9.8m/s^2 d=? t=2.3s d=(u+v/2)t d=(23+0/2)(2.3) d=26m so the maximum height would be 26m at 2.3s?