An insect is resting above the water level on a leaf, a horizontal 0.600 m away from a fish. The fish shoots water into the air above the surface of the water at a 60 degree angle, with an initial velocity of 3.01 m/s.
Assume the fish shoots the water into the air at water level, and that the water hits the insect.
At what height is the leaf above water level?
v = vi + at
x = vi(t) + 0.5a(t^2)
The Attempt at a Solution
First I tried to find out how much time it would take the water to travel in the horizontal direction.
Initial velocity in horizontal direction: cos60*3.01= 1.505 m/s
With zero acceleration, the time it would take to travel 0.600 m would be:
Then, I tried to figure out where the water would be at 0.398 seconds vertically.
Its initial velocity is sin60*3.01 = 2.60 m/s
2.60(0.398)+(0.5)(-9.81)(0.398^2)= 0.259 m
I must be doing something wrong because the program says I have the wrong answer. I have no idea where the problem is, though... any ideas?