Projectile Motion(Rocket)

  • Thread starter Toranc3
  • Start date
  • #1
189
0

Homework Statement



When it is 145 m above the ground, a rocket traveling vertically upward at a constant 8.50 m/s relative to the ground launches a secondary rocket at a speed of 12 m/s at an angle of 53 degrees above the horizontal, both quantities being measured by an astronaut sitting in the rocket. Air resistance is too small to worry about.

(a) Just as the secondary rocket is launched, what are the horizontal and vertical components of its velocity relative to (i) the astronaut sitting in the rocket and (ii) Mission Control on the ground?

(b) Find the initial speed and launch angle of the secondary rocket as measured by mission control.

(c) What maximum height above the ground does the secondary rocket reach?



Homework Equations



Vy=Vosin(θ)
Vx=Vocos(θ)

Vr2/e=Vr2/r1+Vr1/e

Vr2/e= velocity of rocket 2 relative to earth
Vr2/r1= velocity of rocket 2 relative to rocket 1
Vr1/e= velocity of rocket 1 relative to earth

The Attempt at a Solution


A)
i:
Vr2/r1-x= 12m/s*cos(53)=7.2217 m/s
Vr2/r1-y= 12m/s*sin(53)=9.5836 m/s

Vr2/e=vr2/r1 + vr1/e

ii: Vr2/e-y=vr2/r1-y + vr1/e-y
Vr2/3-y= 9.5836 m/s + 8.50m/s=18.0836m/s

Vr2/e-x=vr2/r1-x + vr1/e-x
vr2/e-x= 7.2217m/s + 0=7.2217m/s

Do I have part a right so far? thanks!
 

Answers and Replies

  • #2
Doc Al
Mentor
44,994
1,269
Do I have part a right so far? thanks!
Looks good to me!
 
  • #3
189
0

Related Threads on Projectile Motion(Rocket)

  • Last Post
Replies
2
Views
933
  • Last Post
Replies
15
Views
4K
  • Last Post
Replies
2
Views
8K
  • Last Post
Replies
1
Views
2K
Replies
8
Views
4K
Replies
3
Views
1K
Replies
7
Views
11K
  • Last Post
Replies
4
Views
2K
  • Last Post
Replies
5
Views
2K
  • Last Post
3
Replies
53
Views
970
Top