Ok, in this problem, only the y direction is dealt with Here is the problem You are standing on top of a building, 30 m above the ground. You throw a ball (m = 0.15 kg) with an initial velocity or 20 m/s (in the y direction). Air resistance is given as (1/30)*v (yet again only considering the y direction because range is not an issue here). a) find the maximum height of the ball b) find the time t when the ball hits the ground 30 m below you Ok so I set it up like this mv' = -mg - v(1/30) v' = -g - v(1/30m) from here I get kind of confused. I tried this v' + v(1/30m) = -g (e^(t/30m)v)' = -ge^(t/30m) integrating: e^(t/30m)v = -30mge^(t/30m) + c v = -30mg + c/(e^(t/30m)) I'm pretty sure I'm wrong by here. Help would be appreciated.