A jet is flying 200 feet above a level plain at 800 mph. Suddenly, the ground begins to rise at a 5 degree slope. How much time does the pilot have to raise the nose before the aircraft strikes the ground? I came up with (200tan(85))/(800x1.466) seconds. The 1.466 converts the initial velocity from mph to ft/s, and the 200tan(85) is the distance to the point where the 5 degree slope breaks the level plane. Can anyone double check this and correct me if I made a mistake?