Ok I think i am getting the hang of this stuff. But, A rookie quaterback throws a football with an initial upward velocity component of 16.0 m/s and a horizontal velocity component of 19.0 m/s. Ignore air resistance. a. how much time is required for the ball to reach the highes point of trajectory? Ok I did 19=1/2(9.8)t^2 to get my time which comes out to 1.96. However, it said the answer is wrong, but i used the y=1/2gt^2 because it is in the horizontal direction. b. how high is this point? c. how much time after it is thrown for the ball to reach its original level? i thought this would be the same as part A d. how far has it traveled horizontally during this time? i know i would use d=vt, but i would need to know my time which i dont see how it is incorrect. oh wait, should i have used 16 in place of the 19?