1. The problem statement, all variables and given/known data An object was launched from the top of a cliff at some angle with an acceleration of 50 ft/sec that overcame gravity. The fuel tank ran out after 2 seconds of flight and gravity took over from that point forward. The object reached a maximum height of 310 ft, was in the air for a total of 9.16 seconds and traveled a horizontal distance of 383 ft. Find: Initial Launch Angle Height of the cliff Initial vertical velocity Initial horizontal velocity 2. Relevant equations s(t)=1/2at^2+vt+s d=1/2at^2 Vf=Vi+at 3. The attempt at a solution I think I may have found the launch angle by using the 1/2at^2 equation and plugging in 383=1/2ax(9.16)^2 and 310=1/2ay(9.16)^2. I found the angle to be 39.36, but I am unsure if it is correct, after that I am stuck, help is greatly appreciated.