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Projectile Motion

  1. Nov 12, 2007 #1
    When you kick a ball of mass m into the air at a speed v0 at an angle theta to the ground, how do you know that the maximum distance in the x direction that the ball can travel occurs at 45 degrees.

    Can someone show me the calculation of how this happens?
     
  2. jcsd
  3. Nov 12, 2007 #2

    andrevdh

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    Homework Helper

    The formula for the range, [tex]R[/tex], of a projectile has a term

    [tex]\sin(2\alpha)[/tex]

    where [tex]\alpha[/tex] is the launch angle above the horizon. This means that the range will be a maximum when the projectile is launched such that

    [tex]2\alpha = 90^o[/tex]
     
  4. Nov 12, 2007 #3
    thanks! how did u get that equation. is it possible to derive it from the kinematics equations? THanks!

    nvm i think i did it
     
    Last edited: Nov 12, 2007
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