1. The problem statement, all variables and given/known data A bastketball player is 2m tall and stands 10m from the basket.The height of the basket is 3m and the player throws the ball with speed 11m/s. At what angle with respect to the horizontal should he throw the ball so that is goes through to basket? 2. Relevant equations g=gravity, h= maximum height vi= initial velocity x=angle R= maximum range h=vi^2 * (sin(x))^2 / 2g R= vi^2 * sin 2x /g 3. The attempt at a solution Here is what've done: h=vi^2 * (sin(x))^2 / 2g x= Inverse SIN (SQRT ( h*2g / vi^2 )) height = 1m x= Inverse Sin(SQRT (1*2(9.8)/ 11^2)) = 23.73 degree R= vi^2 * sin 2x /g x= (Inverse SIN(R*g / vi^2)) / 2 R= 10m x= (Inverse SIN(10*9.8 / 11^2)) / 2 = 27.04degree both angles aint the same, is it because the height of the basket is different to the player's height? do i need to put "h=vi^2 * (sin(x))^2 / 2g " and "R= vi^2 * sin 2x /g " into one eqn in order to get the angle?