1. The problem statement, all variables and given/known data shot from 60 degrees 128 cm above ground, a metal ball lands 86.5 cm away. what is max height the ball reaches? 2. Relevant equations d=v1 t + 1/2 a tsquared v2squared = v1squared + 2ad d= 1/2(v1 + v2)t a=(v2-v1) / t 3. The attempt at a solution without having my initial velocity, time, i am having trouble solving for how the max height the ball will reach . i am trying to solve the vertical displacement being the Vy and the horizontal displacement being the Vx to find out the hypotenuse of the triangle( with angels 60, 30, 90), and i am so lost. i know i have my acceleration due to gravity, and my V2y=0m/s and my angel of elevation is 60 degrees but i am so lost in figuring out max height the ball will reach because i have so many unknowns. can anyone help?