(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

shot from 60 degrees 128 cm above ground, a metal ball lands 86.5 cm away.

what is max height the ball reaches?

2. Relevant equations

d=v1 t + 1/2 a tsquared

v2squared = v1squared + 2ad

d= 1/2(v1 + v2)t

a=(v2-v1) / t

3. The attempt at a solution

without having my initial velocity, time, i am having trouble solving for how the max height the ball will reach .

i am trying to solve the vertical displacement being the Vy and the horizontal displacement being the Vx to find out the hypotenuse of the triangle( with angels 60, 30, 90), and i am so lost. i know i have my acceleration due to gravity, and my V2y=0m/s and my angel of elevation is 60 degrees but i am so lost in figuring out max height the ball will reach because i have so many unknowns.

can anyone help?

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# Projectile motion

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