1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Projectile Motion

  1. Mar 5, 2009 #1
    I have 2 question.


    1) In projectile motion is the velocity in the x compontent constant, while above the release point?

    2) Is Y = Voy * t - 0.5 * 9.81 * t^2 the equation used to find the heigth at any given time?


    Thank You.
     
  2. jcsd
  3. Mar 6, 2009 #2

    S_Happens

    User Avatar
    Gold Member

    1) If you ignore any forces acting on the projectile (and for basic courses and simplicity you usually do) or consider them to be zero, then yes.

    2) If your initial position is zero, then yes. In a question where a projectile is dropped from a height (one that would have a "release point") typically you would use that height as the initial position.
    Edit- The "Y" would be instantaneous position in the y component. The initial "Y" would be inserted on the right side of the equation. (Y = Yinitial+ Voy*t - 0.5*9.81*t^2)
     
    Last edited: Mar 6, 2009
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook