Projectile Motion: Questions on Velocity & Height

[soul5]

I have 2 question.


1) In projectile motion is the velocity in the x compontent constant, while above the release point?

2) Is Y = Voy * t - 0.5 * 9.81 * t^2 the equation used to find the heigth at any given time?


Thank You.

 

[S_Happens]

1) If you ignore any forces acting on the projectile (and for basic courses and simplicity you usually do) or consider them to be zero, then yes.

2) If your initial position is zero, then yes. In a question where a projectile is dropped from a height (one that would have a "release point") typically you would use that height as the initial position.
Edit- The "Y" would be instantaneous position in the y component. The initial "Y" would be inserted on the right side of the equation. (Y = Y_initial+ Voy*t - 0.5*9.81*t^2)

 

[astrokreng]

1) Yes, in projectile motion, the velocity in the x component remains constant while the object is above the release point. This is because there is no force acting on the object in the horizontal direction, so it will continue to move at a constant speed in that direction. However, the velocity in the y component will change due to the force of gravity acting on the object.

2) Yes, the equation Y = Voy * t - 0.5 * 9.81 * t^2 is commonly used to find the height of an object at any given time during projectile motion. This equation takes into account the initial vertical velocity (Voy), the time (t) since the object was released, and the acceleration due to gravity (9.81 m/s^2). It is derived from the kinematic equations of motion and can be used to calculate the height at any point in the object's trajectory.