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Projectile Motion

  1. Sep 28, 2009 #1
    A Major league pitcher can throw a ball in excess of 41.3m/s. If a ball is thrown horizontally at this speed, how much will it drop by the time it reaches a catcher who is 17.0m away from the point of release?
    So Ay=-9.8
    X=17m
    t=?
    Vox=0
    V=41.3
    y=(Vy^2-Voy^2)2g
    I thoguht i would use this formular but wasnt sure how to figure Voy out since Vy=0...
    Please help!
     
  2. jcsd
  3. Sep 29, 2009 #2

    Redbelly98

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    Vox, the initial horizontal speed, is not 0, it is ____?
    Also, ax = ____?

    Can you fill in the blanks, and then use this information to find t?
     
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