A Major league pitcher can throw a ball in excess of 41.3m/s. If a ball is thrown horizontally at this speed, how much will it drop by the time it reaches a catcher who is 17.0m away from the point of release? So Ay=-9.8 X=17m t=? Vox=0 V=41.3 y=(Vy^2-Voy^2)2g I thoguht i would use this formular but wasnt sure how to figure Voy out since Vy=0... Please help!