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a tennis player standing 12.3 m from the net hits the ball at 3° above the horizontal. to clear the net the ball must rise at least 0.33m. if the ball just clears the net at the apex of its trajectory, how fast was the ball moving when it left the racket?

my answer was found by the equation u^2/2g = d (0.33m)

so 0.33m x 19.6 ms^2 = 6.47 ms

the square root of 6.47 ms

= 2.54 ms

Is this right?

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# Homework Help: Projectile motion

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