magnifik said:Homework Equations
y=v0sin([tex]\phi[/tex])t - 1/2gt^2
vy=v0sin([tex]\phi[/tex]) - gt
The Attempt at a Solution
how do i account for initial height?
The time of flight of a cannon ball does not directly affect its velocity. However, the longer the time of flight, the more air resistance and gravity will act on the ball, causing it to slow down.
The velocity of a cannon ball can be calculated using the formula v = √(2gh), where v is the velocity in meters per second, g is the acceleration due to gravity (9.8 m/s2), and h is the height of the cannon above the ground in meters. This formula assumes that air resistance is negligible.
Yes, a cannon ball can reach a velocity of zero if it reaches its maximum height and then begins to fall back to the ground. At this point, the ball's velocity will decrease until it reaches zero at the highest point of its trajectory.
Air resistance, also known as drag, acts in the opposite direction of an object's motion and can significantly slow down a cannon ball. The greater the surface area of the ball and the faster it travels, the more air resistance will affect its velocity.
Yes, the velocity of a cannon ball can be changed mid-flight by altering the angle at which the cannon is fired or by adding external forces such as wind or propulsion. Additionally, air resistance and gravity will continue to affect the ball's velocity throughout its flight.